lua脚本如下
最原始的解题方法 local str{} local i, j, k0, 0, 0 for i1, 4 do for j1, 4 do for k1, 4 do if i~j and i~k and j~k then str[#str1]i..j..k end end end end print("组成的数有"..#str) print(table.unpack(str)) 运行的结果如下 组成的数有24 1…
遇到问题:qt.qpa.xcb: could not connect to display 解决办法,在命令行输入:
export DISPLAY:0
然后重新跑python程序,解决!
参考博客:qt.qpa.xcb: could not connect to displayqt.qpa.plugin: Could …